-1,10,17
10
49,,,,1
1
5
49
0
1
2
48
 LETS DEMONSTRATE THE TRACE FEATURE
49,0,1,3,3
1,1
1,2
1,1,2
1
48
 LETS TEST ALL THE INTERNAL AND ONE EXTERNAL FORMATS
-1
(1H ,10(F8.2,2X))
-1,1
-1,2
-1,3
0
1,2
2,1,2
2,1,2,1
2,1,2,2
2,1,2,3
49
0
1,3
2
3,1,2
3,2,1,3
0
1,4
2
4,1,2
0
1,5
4
5,1,1,3
-1
(1H ,F7.3,F5.0,2F5.0)
0
1,6
6
1
6
7
8
7,3
0.05,0.07,0.09
48
 BAD WE MUST HAVE A 1,15 BEFORE THIS SHEFFE SO LETS DO THAT
1,15
48
 NOW IT SHOULD WORK WE HOPE
7
0
1,8
6
1
8
7
48,3
		NOW WE TEST THE NONPARAMETRICS
	STARTING WITH WILCOXON
	IF YOU ARE WATCHING HERE IS WERE PROCESS SLOWS DOWN
0
1,13
4
13,1,2
13,3,4
0
1,14
4
14,1,2
14,3,4
0
1,15
3
15
15,1
0
1,16
2
16,1,2,3
0
1,17
3
17
0
1,1
2,1,2
48,2
 NOW LETS TRY SOME AREAS
 THE DATA IN GROUP 1 WILL DO NICELY
18,2,1
18,1,2,1
18,2,1
0
1,5
4
48
 FOR TESTING RUTINE 19 WE CAN UTILIZE THE GROUP 5 DATA
19
19,1
19,4
48
 THE SAME DATA WILL DO US FINE FOR CROSSTABS AND PLOTTS TOO
20,1,2
20,1,2,10
20,1,1
21,1,2,10
21,1,2,50
21,2,1,100
21,2,1,150
48,3
 NOW WE TEST THE TRANSFORMATIONS LOGIC
 WE COULD USE THE SAME DATA
 AND WHY NOT ?
22,1
-1,2
22,-1
-1,2
22,1,5,1
22,1,6,2
22,1,7,3
22,1,8,4
22,1,9,5
22,1,10,6
48,2
 NOW WE HAVE THE FULL COMPLEMENT OF COLUMNS
 LETS CHECK THEM
-1,3
48
 HOW ABOUT PLOTTING SOME OF THEM BUT LETS KEEP THE PLOT SMALL
21,1,5,10
21,1,6,10
21,1,7,10
21,1,8,10
21,1,9,10
48
 AND WHY NOT A LOG BY LOG PLOT OF 1 AND 2 ?
21,6,2,110
48
 NOW TRY RE-SETTING THE DATA AREA TO 2 COLUMNS FIRST WITHOUT THE ATT
22,10,2,-1
48
 NO WELL SET THE ATT SWITCH
49,1
22,10,2,-1
49,0
1
48,10
 WELL THATS ALLMOST ALL  THE PROGRAM WILL NOW LOOP THE REMAINING
 CARDS FROM THE FIRST -1 REQUEST

 IMPRESSED ??

        I AM

   THANKS DEC FOR SUCH CUMPUTING POWER IN A 12K 12 BIT MACHINE

 LARS PALMER   HASSLE   SWEDEN
50